## Single phase Amps to VA calculation formula

S_{(VA)} = I_{(A)} × V_{(V)}

The apparent power **S** in volt-amps (VA) is equal to the phase current **I** in amps (A), multiplied by the RMS voltage **V** in volts (V).

So,

*VA = A x V *

*volt-amps = amps x volts*

**For example:**

*Phase current (I) = 2,5A*

*Voltage (V) = 110V*

*Power (S) = 2,5A x 110V = 275VA*

## 3 phase Amps to VA calculation formula

### Line to line voltage

S_{(VA)} = √3 × I_{(A)} × V_{L-L(V)}

The apparent power **S** in volt-amps (VA) is equal to square root of 3, multiplied by the phase current **I** in amps (A), multiplied by the line to line RMS voltage **V**_{L-L} in volts (V).

So,

*VA = √3 × A x V*

*volt-amps = √3 × amps x volts*

**For example:**

*Phase current (I) = 2,5A*

*Voltage (V) = 110V*

*Power (S) = √3 x 2,5A x 110V = 476,3VA*

### Line to neutral voltage

S_{(VA)} = 3 × I_{(A)} × V_{L-N(V) }

The apparent power **S** in volt-amps (VA) is equal to 3, multiplied by the phase current **I** in amps (A), multiplied by the line to neutral RMS voltage **V**_{L-N} in volts (V).

So,

*VA = 3 × A x V*

*volt-amps = 3 × amps x volts*

**For example:**

*Phase current (I) = 2,5A*

*Voltage (V) = 110V*

*Power (S) = 3 x 2,5A x 110V = 825VA*