## DC watts to amps calculation formula

I_{(A)} = P_{(W)} / V_{(V)}

The current **I** in amps (A) is equal to the power **P** in watts (W), divided by the voltage **V** in volts (V).

So,

*A = W / V*

*amp = watt / volt*

**For example:**

*Power (P) = 220W*

*Voltage (V) = 110V*

*Phase current (I) = 220W / 110V = 2A*

## AC single phase watts to amps calculation formula

I_{(A)} = P_{(W)} / (PF × V_{(V)})

The phase current **I** in amps (A) is equal to the power **P** in watts (W), divided by the power factor **PF**, multiplied by the RMS voltage **V** in volts (V).

So,

*A = W / (PF x V)*

*amp = watt / (PF x volt)*

**For example:**

*Power (P) = 220W*

*Voltage (V) = 110V*

*PF = 0,7*

*Phase current (I) = 220W / (0,7 x 110V) = 2,86A*

## AC three phase watts to amps calculation formula

### Line to line voltage

I_{(A)} = P_{(W)} / (√3 × PF × V_{L-L(V)})

The phase current **I** in amps (A) is equal to the power **P** in watts (W), divided by square root of 3, multiplied by the power factor **PF**, multiplied by the line to line RMS voltage **V**_{VL-L} in volts (V).

So,

*A = W / (√3 × PF x V)*

*amp = watt / (√3 × PF x volt)*

**For example:**

*Power (P) = 220W*

*Voltage (V) = 110V*

*PF = 0,7*

*Phase current (I) = 220W / (√3 × 0,7 x 110V) = 1,65A*

### Line to neutral voltage

I_{(A)} = P_{(W)} / (3 × PF × V_{L-N(V)})

The phase current **I** in amps (A) is equal to the power **P** in watts (W), divided by 3, multiplied by the power factor **PF**, multiplied by the line to neutral RMS voltage **V**_{VL-N} in volts (V).

So,

*A = W / (3 × PF x V)*

*amp = watt / (3 × PF x volt)*

**For example:**

*Power (P) = 220W*

*Voltage (V) = 110V*

*PF = 0,7*

*Phase current (I) = 220W / (3 × 0,7 x 110V) = 0,95A*