## DC Amps to watts calculation formula

P_{(W)} =I_{(A)} × V_{(V)}

The power **P** in watts (W) is equal to the phase current **I** in amps (A), multiplied by the voltage **V** in volts (V).

So,

*W = A x V*

*watts = amps x volts*

**For example:**

*Phase current (I) = 2,5A*

*Voltage (V) = 110V*

*Power (P) = 2,5A x 110V = 275W*

## AC single phase Amps to watts calculation formula

P_{(W)} = PF × I_{(A)} × V_{(V)}

The real power **P** in watts (W) is equal to the power factor **PF**, multiplied by the phase current **I** in amps (A), multiplied by the RMS voltage **V** in volts (V).

So,

*W = PF x A x V*

*watts = PF x amps x volts*

**For example:**

*Phase current (I) = 2,5A*

*Voltage (V) = 110V*

*PF = 0,7*

*Power (P) = 0,7 x 2,5A x 110V = 192,5W*

## AC three phase Amps to watts calculation formula

### Line to line voltage

P_{(W)} = √3 × PF × I_{(A)} × V_{L-L (V)}

The real power **P** in watts (W) is equal to square root of 3, multiplied by the power factor **PF**, multiplied by the phase current **I** in amps (A), multiplied by the line to line RMS voltage **V**_{L-L} in volts (V).

So,

*W = √3 x PF x A x V*

*watts = √3 x PF x amps x volts*

**For example:**

*Phase current (I) = 2,5A*

*Voltage (V) = 110V*

*PF = 0,7*

*Power (P) = √3 x 0,7 x 2,5A x 110V = 333,4W*

### Line to neutral voltage

P_{(W)} = 3 × PF × I_{(A)} × V_{L-N (V)}

The real power **P** in watts (W) is equal to 3, multiplied by the power factor **PF**, multiplied by the phase current **I** in amps (A), multiplied by the line to neutral RMS voltage **V**_{L-N} in volts (V).

So,

*W = 3 x PF x A x V*

*watts = 3 x PF x amps x volts*

**For example:**

*Phase current (I) = 2,5A*

*Voltage (V) = 110V*

*PF = 0,7*

*Power (P) = 3 x 0,7 x 2,5A x 110V = 577,5W*