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Quadratic equation is a second order polynomial with 3 coefficients – a, b, c.

The quadratic equation is given by:

ax+ bx + c = 0

The solution to the quadratic equation is given by 2 numbers x1 and x2.

We can change the quadratic equation to the form of:

(x – x1)(x – x2) = 0

The solution to the quadratic equation is given by the quadratic formula:

The expression inside the square root is called discriminant and is denoted by Δ:

Δ = b2 – 4ac

The quadratic formula with discriminant notation:

This expression is important because it can tell us about the solution:

• When Δ>0, there are 2 real roots x1=(-b+√Δ)/(2a) and x2=(-b-√Δ)/(2a).
• When Δ=0, there is one root x1=x2=-b/(2a).
• When Δ<0, there are no real roots, there are 2 complex roots:
x1=(-b+i√-Δ)/(2a) and x2=(-b-i√-Δ)/(2a).

### Problem #1

5x2+8x+3 = 0

solution:

a = 5, b = 8, c = 3
x1,2 = (-8 ± √(82 – 4×5×3)) / (2×5) = (-8 ± √(4)) / 10 = (-8 ± 2) / 10
x1 = (-8 + 2) / 10 = -6/10 = -0.6
x2 = (-8 – 2) / 10 = -1

### Problem #2

4x– 7x + 1 = 0

solution:

a = 4, b = -7, c = 1
x1,2 = (7 ± √((-7)2 – 4×4×1)) / (2×4) = (7 ± √(49 – 16)) / 8 = (7 ± 5,74) / 8
x1 ≈ 1,59  ; x2 ≈ 0,157

### Problem #3

x2 + 2x + 5 = 0

solution:

a = 1, b = 2, c = 5
x1,2 = (-2 ± √(22 – 4×1×5)) / (2×1) = (-2 ± √(4-20)) / 2 = (-2 ± √(-16)) / 2

There are no real solutions. The values are complex numbers:

x= -1 + 2i
x= -1 – 2i

The quadratic function is a second order polynomial function:

f(x) = ax2 + bx + c

The solutions to the quadratic equation are the roots of the quadratic function, that are the intersection points of the quadratic function graph with the x-axis, when

f(x) = 0

When there are 2 intersection points of the graph with the x-axis, there are 2 solutions to the quadratic equation.

When there is 1 intersection point of the graph with the x-axis, there is 1 solution to the quadratic equation.

When there are no intersection points of the graph with the x-axis, we get not real solutions (or 2 complex solutions).